pop() removes the element at the position specified in the parameter.
so it remove the value of index 1 which is 4 so after pop the list will be [3, 5, 20, 5, 25, 1, 3]
What will be the output of the following Python code?
>>>"Welcome to Python".split()
mylist=list("a#b#c#d".split('#')) print(mylist)
निम्नलिखित Python कोड का आउटपुट क्या होगा?
myList = [1, 5, 5, 5, 5, 1] max = myList[0] indexOfMax = 0 for i in range(1, len(myList)): if myList[i] > max: max = myList[i] indexOfMax = i print(indexOfMax)
myList = [1, 2, 3, 4, 5, 6] for i in range(1, 6): myList[i - 1] = myList[i] for i in range(0, 6): print(myList[i], end = " ")
list1 = [1, 3] list2 = list1 list1[0] = 4 print(list2)
def f(values): values[0] = 44 v = [1, 2, 3] f(v) print(v)
values = [[3, 4, 5, 1], [33, 6, 1, 2]] v = values[0][0] for row in range(0, len(values)): for column in range(0, len(values[row])): if v < values[row][column]: v = values[row][column] print(v)
values = [[3, 4, 5, 1], [33, 6, 1, 2]] v = values[0][0] for lst in values: for element in lst: if v > element: v = element print(v)
values = [[3, 4, 5, 1 ], [33, 6, 1, 2]] for row in values: row.sort() for element in row: print(element, end = " ") print()
matrix = [[1, 2, 3, 4], [4, 5, 6, 7], [8, 9, 10, 11], [12, 13, 14, 15]] for i in range(0, 4): print(matrix[i][1], end = " ")
def m(list): v = list[0] for e in list: if v < e: v = e return v values = [[3, 4, 5, 1], [33, 6, 1, 2]] for row in values: print(m(row), end = " ")
data = [[[1, 2], [3, 4]], [[5, 6], [7, 8]]] def ttt(m): v = m[0][0] for row in m: for element in row: if v < element: v = element return v print(ttt(data[0]))
points = [[1, 2], [3, 1.5], [0.5, 0.5]] points.sort() print(points)