When associativity is doubled, then the set offset will be effected, accordingly, the number of bits used for TAG comparator be effected.
Width of set index decoder also will be effected when set offset is changed.
Width of wag selection multiplexer wil be effected when the block offset is changed.
With of processor to main memory data bus is guaranteed to be NOT effected.
In the Newton-Raphson method, an initial guess of x0 = 2 is made and the sequence x0, x1, x2 ……… is obtained for the function 0.75x3 - 2x2 - 2x + 4 = 0 Consider the statements (I) x3 =0. (II) The method converges to a solution in a finite number of iterations. Which of the following is TRUE?
Also, root does not lies between 0 and 1. So, the method diverges if x0 = 2 ∴ only (I) is true.
Consider the following relation on subsets of the set S of integers between 1 and 2014. For two distinct subsets U and V of S we say U < V if the minimum element in the symmetric difference of the two sets is in U.
Consider the following two statements: S1: There is a subset of S that is larger than every other subset. S2: There is a subset of S that is smaller than every other subset. Which one of the following is CORRECT?
From given data S1 is true, since null set is larger than every other set, and S2 is true since the universal set
{1,2,...,2014} is smaller than every other set.
Both s1 and s2 are true.
SQL allows duplicate tuples in relations, and correspondingly defines the multiplicity of tuples in the result of joins. Which one of the following queries always gives the same answer as the nested query shown below:
Select * from R where a in (select S. a from S)
Consider the following instances of R & S O/P of given nested query is A) O/P:- multiplicity of tuples is disturbed B) O/P:- C) O/P:- Multiplicity of tuples is maintained Multiplicity of duplicate tuples will be distributed when there is a match between R.a and S.a and for that match S.a’s value is repeated.
Given 8 – bit delimiter pattern of 01111110.
Output Bit string after stuffing is
StuffedBit
Now, Input String is 0111110101
A. One of the main functionality of Network Layer is Routing. So, Option A.is CORRECT.
B. Bit Synchronization is always handled by Physical Layer of OSI model but not Data Link Layer. So
Option B. is INCORRECT.
C. End – to – End Process Communication is handled by Transport Layer. So Option C. is CORRECT.
D. MAC sub layer has 3 types of protocols (Random, Controlled and Channelized Access).